Left Termination of the query pattern
reverse_concatenate_in_3(g, g, a)
w.r.t. the given Prolog program could successfully be proven:
↳ Prolog
↳ PrologToPiTRSProof
Clauses:
concatenate([], L, L).
concatenate(.(X, L1), L2, .(X, L3)) :- concatenate(L1, L2, L3).
member(X, .(X, L)).
member(X, .(Y, L)) :- member(X, L).
reverse(L, L1) :- reverse_concatenate(L, [], L1).
reverse_concatenate([], L, L).
reverse_concatenate(.(X, L1), L2, L3) :- reverse_concatenate(L1, .(X, L2), L3).
Queries:
reverse_concatenate(g,g,a).
We use the technique of [30]. With regard to the inferred argument filtering the predicates were used in the following modes:
reverse_concatenate_in: (b,b,f)
Transforming Prolog into the following Term Rewriting System:
Pi-finite rewrite system:
The TRS R consists of the following rules:
reverse_concatenate_in_gga([], L, L) → reverse_concatenate_out_gga([], L, L)
reverse_concatenate_in_gga(.(X, L1), L2, L3) → U4_gga(X, L1, L2, L3, reverse_concatenate_in_gga(L1, .(X, L2), L3))
U4_gga(X, L1, L2, L3, reverse_concatenate_out_gga(L1, .(X, L2), L3)) → reverse_concatenate_out_gga(.(X, L1), L2, L3)
The argument filtering Pi contains the following mapping:
reverse_concatenate_in_gga(x1, x2, x3) = reverse_concatenate_in_gga(x1, x2)
[] = []
reverse_concatenate_out_gga(x1, x2, x3) = reverse_concatenate_out_gga(x3)
.(x1, x2) = .(x1, x2)
U4_gga(x1, x2, x3, x4, x5) = U4_gga(x5)
Infinitary Constructor Rewriting Termination of PiTRS implies Termination of Prolog
↳ Prolog
↳ PrologToPiTRSProof
↳ PiTRS
↳ DependencyPairsProof
Pi-finite rewrite system:
The TRS R consists of the following rules:
reverse_concatenate_in_gga([], L, L) → reverse_concatenate_out_gga([], L, L)
reverse_concatenate_in_gga(.(X, L1), L2, L3) → U4_gga(X, L1, L2, L3, reverse_concatenate_in_gga(L1, .(X, L2), L3))
U4_gga(X, L1, L2, L3, reverse_concatenate_out_gga(L1, .(X, L2), L3)) → reverse_concatenate_out_gga(.(X, L1), L2, L3)
The argument filtering Pi contains the following mapping:
reverse_concatenate_in_gga(x1, x2, x3) = reverse_concatenate_in_gga(x1, x2)
[] = []
reverse_concatenate_out_gga(x1, x2, x3) = reverse_concatenate_out_gga(x3)
.(x1, x2) = .(x1, x2)
U4_gga(x1, x2, x3, x4, x5) = U4_gga(x5)
Using Dependency Pairs [1,30] we result in the following initial DP problem:
Pi DP problem:
The TRS P consists of the following rules:
REVERSE_CONCATENATE_IN_GGA(.(X, L1), L2, L3) → U4_GGA(X, L1, L2, L3, reverse_concatenate_in_gga(L1, .(X, L2), L3))
REVERSE_CONCATENATE_IN_GGA(.(X, L1), L2, L3) → REVERSE_CONCATENATE_IN_GGA(L1, .(X, L2), L3)
The TRS R consists of the following rules:
reverse_concatenate_in_gga([], L, L) → reverse_concatenate_out_gga([], L, L)
reverse_concatenate_in_gga(.(X, L1), L2, L3) → U4_gga(X, L1, L2, L3, reverse_concatenate_in_gga(L1, .(X, L2), L3))
U4_gga(X, L1, L2, L3, reverse_concatenate_out_gga(L1, .(X, L2), L3)) → reverse_concatenate_out_gga(.(X, L1), L2, L3)
The argument filtering Pi contains the following mapping:
reverse_concatenate_in_gga(x1, x2, x3) = reverse_concatenate_in_gga(x1, x2)
[] = []
reverse_concatenate_out_gga(x1, x2, x3) = reverse_concatenate_out_gga(x3)
.(x1, x2) = .(x1, x2)
U4_gga(x1, x2, x3, x4, x5) = U4_gga(x5)
U4_GGA(x1, x2, x3, x4, x5) = U4_GGA(x5)
REVERSE_CONCATENATE_IN_GGA(x1, x2, x3) = REVERSE_CONCATENATE_IN_GGA(x1, x2)
We have to consider all (P,R,Pi)-chains
↳ Prolog
↳ PrologToPiTRSProof
↳ PiTRS
↳ DependencyPairsProof
↳ PiDP
↳ DependencyGraphProof
Pi DP problem:
The TRS P consists of the following rules:
REVERSE_CONCATENATE_IN_GGA(.(X, L1), L2, L3) → U4_GGA(X, L1, L2, L3, reverse_concatenate_in_gga(L1, .(X, L2), L3))
REVERSE_CONCATENATE_IN_GGA(.(X, L1), L2, L3) → REVERSE_CONCATENATE_IN_GGA(L1, .(X, L2), L3)
The TRS R consists of the following rules:
reverse_concatenate_in_gga([], L, L) → reverse_concatenate_out_gga([], L, L)
reverse_concatenate_in_gga(.(X, L1), L2, L3) → U4_gga(X, L1, L2, L3, reverse_concatenate_in_gga(L1, .(X, L2), L3))
U4_gga(X, L1, L2, L3, reverse_concatenate_out_gga(L1, .(X, L2), L3)) → reverse_concatenate_out_gga(.(X, L1), L2, L3)
The argument filtering Pi contains the following mapping:
reverse_concatenate_in_gga(x1, x2, x3) = reverse_concatenate_in_gga(x1, x2)
[] = []
reverse_concatenate_out_gga(x1, x2, x3) = reverse_concatenate_out_gga(x3)
.(x1, x2) = .(x1, x2)
U4_gga(x1, x2, x3, x4, x5) = U4_gga(x5)
U4_GGA(x1, x2, x3, x4, x5) = U4_GGA(x5)
REVERSE_CONCATENATE_IN_GGA(x1, x2, x3) = REVERSE_CONCATENATE_IN_GGA(x1, x2)
We have to consider all (P,R,Pi)-chains
The approximation of the Dependency Graph [30] contains 1 SCC with 1 less node.
↳ Prolog
↳ PrologToPiTRSProof
↳ PiTRS
↳ DependencyPairsProof
↳ PiDP
↳ DependencyGraphProof
↳ PiDP
↳ UsableRulesProof
Pi DP problem:
The TRS P consists of the following rules:
REVERSE_CONCATENATE_IN_GGA(.(X, L1), L2, L3) → REVERSE_CONCATENATE_IN_GGA(L1, .(X, L2), L3)
The TRS R consists of the following rules:
reverse_concatenate_in_gga([], L, L) → reverse_concatenate_out_gga([], L, L)
reverse_concatenate_in_gga(.(X, L1), L2, L3) → U4_gga(X, L1, L2, L3, reverse_concatenate_in_gga(L1, .(X, L2), L3))
U4_gga(X, L1, L2, L3, reverse_concatenate_out_gga(L1, .(X, L2), L3)) → reverse_concatenate_out_gga(.(X, L1), L2, L3)
The argument filtering Pi contains the following mapping:
reverse_concatenate_in_gga(x1, x2, x3) = reverse_concatenate_in_gga(x1, x2)
[] = []
reverse_concatenate_out_gga(x1, x2, x3) = reverse_concatenate_out_gga(x3)
.(x1, x2) = .(x1, x2)
U4_gga(x1, x2, x3, x4, x5) = U4_gga(x5)
REVERSE_CONCATENATE_IN_GGA(x1, x2, x3) = REVERSE_CONCATENATE_IN_GGA(x1, x2)
We have to consider all (P,R,Pi)-chains
For (infinitary) constructor rewriting [30] we can delete all non-usable rules from R.
↳ Prolog
↳ PrologToPiTRSProof
↳ PiTRS
↳ DependencyPairsProof
↳ PiDP
↳ DependencyGraphProof
↳ PiDP
↳ UsableRulesProof
↳ PiDP
↳ PiDPToQDPProof
Pi DP problem:
The TRS P consists of the following rules:
REVERSE_CONCATENATE_IN_GGA(.(X, L1), L2, L3) → REVERSE_CONCATENATE_IN_GGA(L1, .(X, L2), L3)
R is empty.
The argument filtering Pi contains the following mapping:
.(x1, x2) = .(x1, x2)
REVERSE_CONCATENATE_IN_GGA(x1, x2, x3) = REVERSE_CONCATENATE_IN_GGA(x1, x2)
We have to consider all (P,R,Pi)-chains
Transforming (infinitary) constructor rewriting Pi-DP problem [30] into ordinary QDP problem [15] by application of Pi.
↳ Prolog
↳ PrologToPiTRSProof
↳ PiTRS
↳ DependencyPairsProof
↳ PiDP
↳ DependencyGraphProof
↳ PiDP
↳ UsableRulesProof
↳ PiDP
↳ PiDPToQDPProof
↳ QDP
↳ QDPSizeChangeProof
Q DP problem:
The TRS P consists of the following rules:
REVERSE_CONCATENATE_IN_GGA(.(X, L1), L2) → REVERSE_CONCATENATE_IN_GGA(L1, .(X, L2))
R is empty.
Q is empty.
We have to consider all (P,Q,R)-chains.
By using the subterm criterion [20] together with the size-change analysis [32] we have proven that there are no infinite chains for this DP problem. From the DPs we obtained the following set of size-change graphs:
- REVERSE_CONCATENATE_IN_GGA(.(X, L1), L2) → REVERSE_CONCATENATE_IN_GGA(L1, .(X, L2))
The graph contains the following edges 1 > 1